# math

posted by B8

Jesse rents 2 movies and 4 video games for a total of \$18.70. At the same time, Dan rents 3 movies and 2 video games for a total of \$15.25.
How much does their friend Sabrina need to rent a combination of one game and one movie from the same video rental store?
SO I HAD V= VIDEO GAME RENTAL
m= movie rental

2m+4v=18.70
-2(3m+2v=15.25)
2m+4v=18.70
-6m-4v=-30.50
-4m=-11.8
----------
-4 -4 dividing each side by -4
m=\$2.95

Then 2m +4v =18.70
2(2.95)+4v =18.70
5.90+4v=18.70
-5.90 -5.90
4v=12.80
--------
4 4 divide each side by 4
v=\$3.20
2.95 +3.20=\$6.15
the cost for one movie was \$2.95, and the cost for one video game was \$3.20. Sabrina would need a total of \$6.15

Is this correct?
Thanks for checking over my work

1. Bosnian

CORRECT

OR

m = price of movies

v = price of video game

3 m + 2 v = 15.25

-

2 m + 4 v = 18.7
___________________

m - 2 v = - 3.45

m = 2 v - 3.45

3 m + 2 v = 15.25

3 ( 2 v - 3.45 ) + 2 v = 15.25

6 v - 10.35 + 2 v = 15.25

6 v + 2 v = 15.25 + 10.35

8 v = 25.6

v = 25.6 / 8

v = 3.2 \$

m = 2 v - 3.45

m = 2 * 3.2 - 3.45

m = 6.4 - 3.45

m = 2.95 \$

m + v = 2.95 + 3.2 = 6.15 \$

2. B8

Thank you

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