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math

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Jesse rents 2 movies and 4 video games for a total of $18.70. At the same time, Dan rents 3 movies and 2 video games for a total of $15.25.
How much does their friend Sabrina need to rent a combination of one game and one movie from the same video rental store?
SO I HAD V= VIDEO GAME RENTAL
m= movie rental

2m+4v=18.70
-2(3m+2v=15.25)
2m+4v=18.70
-6m-4v=-30.50
-4m=-11.8
----------
-4 -4 dividing each side by -4
m=$2.95

Then 2m +4v =18.70
2(2.95)+4v =18.70
5.90+4v=18.70
-5.90 -5.90
4v=12.80
--------
4 4 divide each side by 4
v=$3.20
2.95 +3.20=$6.15
the cost for one movie was $2.95, and the cost for one video game was $3.20. Sabrina would need a total of $6.15

Is this correct?
Thanks for checking over my work

  • math -

    CORRECT

    OR


    m = price of movies

    v = price of video game



    3 m + 2 v = 15.25

    -

    2 m + 4 v = 18.7
    ___________________

    m - 2 v = - 3.45

    m = 2 v - 3.45


    3 m + 2 v = 15.25

    3 ( 2 v - 3.45 ) + 2 v = 15.25

    6 v - 10.35 + 2 v = 15.25

    6 v + 2 v = 15.25 + 10.35

    8 v = 25.6

    v = 25.6 / 8

    v = 3.2 $


    m = 2 v - 3.45

    m = 2 * 3.2 - 3.45

    m = 6.4 - 3.45

    m = 2.95 $


    m + v = 2.95 + 3.2 = 6.15 $

  • math -

    Thank you

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