A solution of AgI contains 1.2 mol/L Ag+. Ksp of AgI is 8.3×10^17. What is the maximum I− concentration that can exist in this solution?

Answer in units of mol/L

To find the maximum I- concentration that can exist in the solution of AgI, we need to make use of the solubility product constant (Ksp) of AgI. The Ksp expression for AgI is given by:

Ksp = [Ag+][I-]

Given that the solution contains 1.2 mol/L of Ag+, we can substitute this value into the Ksp expression:

8.3×10^17 = (1.2 mol/L) [I-]

To calculate the maximum I- concentration, we can rearrange the equation to solve for [I-]:

[I-] = 8.3×10^17 / (1.2 mol/L)

Now, we can calculate the value:

[I-] ≈ 6.92×10^17 mol/L

Therefore, the maximum I- concentration that can exist in the solution is approximately 6.92×10^17 mol/L.

1.6 x 10^16