with a velocity of 2.3 m/s at an angle of 110 degrees to the board. at what horizontal distance from the end of the board will the diver enter the water?
To find the horizontal distance from the end of the board where the diver enters the water, we can use the horizontal and vertical components of the velocity.
Given:
Initial velocity (v) = 2.3 m/s
Angle (θ) = 110 degrees
Step 1: Find the horizontal component of the velocity.
The horizontal component (Vx) can be calculated using the formula:
Vx = v * cos(θ)
Vx = 2.3 m/s * cos(110 degrees)
Step 2: Find the vertical component of the velocity.
The vertical component (Vy) can be calculated using the formula:
Vy = v * sin(θ)
Vy = 2.3 m/s * sin(110 degrees)
Step 3: Calculate the time of flight.
The time of flight (t) can be determined using the vertical component of velocity:
t = Vy / g
where g is the acceleration due to gravity (approximately 9.8 m/s²).
Step 4: Calculate the horizontal distance traveled.
The horizontal distance (d) can be calculated using the formula:
d = Vx * t
By following these steps, you can find the horizontal distance from the end of the board where the diver enters the water.