A power plant burns coal and generates an average of 600.0 Megawatts (MW) of electrical power while discharging 900.00 MW as waste heat. Find the total electrical energy generated by the plant in a 30-day period.
Coals vary a lot in their energy content. The energy released by the burning of coal is typically between 23 and 33 Mega Joules per kg of coal. The power plant above uses coal rated at 26.7 MJ/kg to heat the boilers. Some of that heat is converted to electrical energy, but most is waste heat discharged into the environment. Assume that it takes about 2.20 kg of oxygen to burn 1 kg of coal (The actual amount varies with the type coal). Find the total mass of the reagents used in operating for 30 days.
Well, now you are getting somewhere.
Go back to the original solution I gave you.
630 MW for 30 days ---> 1.63*10^15 Joules
so 600 MW for 30 days ---> 1.55*10^15 Joules
and 900 MW waste heat ---> 2.33*10^15 Joules
all of which means we must produce
(1.55+2.33)10^15 = 3.88*10^15 Joules with our coal and O2 in 30 days
coal ---> 26.7 *10^6 Joules/Kg
so we need
3.88*10^15/(2.67*10^7) = 1.45*10^8 Kg of coal for 30 days
then we will need 2.2*1.45*10^8 = 3.2*10^8 kg of O2
so
(1.45+3.2)10^8 = 4.64*10^8 Kg reagents
= 464 million Kg of coal and oxygen for 30 days
something is still incorect at the first part..
600*10^6 watts * 30 days * 24 hr/day *3600 seconds/hr = 1.55 * 10^15 Joules
seems to be what I got before
You realize that originally in the earlier problem you gave me a 630 MW plant and later changed it to 600MW ?
yeah, thank's I got it..
sorry for bothering you, you gave me a great help.
To find the total electrical energy generated by the power plant in a 30-day period, we can calculate the energy generated per day and then multiply it by 30.
First, let's find the energy generated per day:
Energy generated per day = 600.0 MW
Next, let's calculate the energy generated in a 24-hour period:
Energy generated in 24 hours = 600.0 MW × 24 hours = 14,400.0 MWh (megawatt-hours)
Since there are 1,000 kilowatt-hours (kWh) in a megawatt-hour (MWh), we can convert the energy to kWh:
Energy generated in 24 hours = 14,400.0 MWh × 1,000 kWh/MWh = 14,400,000.0 kWh
Now, let's multiply the energy generated per day by 30 to find the total electrical energy generated in a 30-day period:
Total electrical energy generated = 14,400,000.0 kWh × 30 = 432,000,000.0 kWh
Therefore, the total electrical energy generated by the power plant in a 30-day period is 432,000,000.0 kilowatt-hours (kWh).
Next, let's move on to calculating the total mass of the reagents used in operating for 30 days.
The energy content of coal is given as 26.7 MJ/kg.
To find the mass of coal burned per day, we need to divide the energy generated per day (in megajoules) by the energy content of coal (in megajoules per kilogram).
Mass of coal burned per day = Energy generated per day / Energy content of coal
Energy generated per day = 600.0 MW × 24 hours = 14,400.0 MWh
Converting MWh to megajoules:
Energy generated per day = 14,400.0 MWh × 1,000 kWh/MWh × 3.6 MJ/kWh = 51,840,000 MJ
Mass of coal burned per day = 51,840,000 MJ / 26.7 MJ/kg ≈ 1,942,694.0 kg
Therefore, the mass of coal burned per day is approximately 1,942,694.0 kilograms.
Now, let's calculate the total mass of coal burned in a 30-day period:
Total mass of coal burned = Mass of coal burned per day × 30 = 1,942,694.0 kg/day × 30 = 58,280,820.0 kg
Since the ratio of oxygen to coal is given as 2.20 kg of oxygen per 1 kg of coal, we can calculate the total mass of oxygen used by multiplying the total mass of coal burned by 2.20:
Total mass of oxygen used = Total mass of coal burned × 2.20 = 58,280,820.0 kg × 2.20 = 128,217,804.0 kg
Therefore, the total mass of the reagents used by the power plant in operating for 30 days is approximately 128,217,804.0 kilograms.