I don't get any of these practice problems.
5. 2(x – 3) = 2x
one solution
no solutions
infinitely many solutions
6. 3(y – 3) = 2y – 9 + y
one solution
no solutions
infinitely many solutions
7. 10x – 2 – 6x = 3x – 2 + x
one solution
no solutions
infinitely many solutions
8. 4(x + 3) + 2x = x – 8
one solution
no solutions
infinitely many solutions
1=B
2=D
3=D
4=A
THANKS WILLOW THERE ARE ONLY THREE ANSWERS FOR THE QUESTIONS SO JUST PUT
B
C
C
A
2(x-3) = 2x
2x - 6 = 2x
Move 2x to the left side and change sign. Then put zero after the equal sign.
2x - 2x - 6 = 0
2x's cancels out.
0 = 6
No Solution
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3(y - 3)= 2y - 9 + y
3y - 9 = 3y - 9
Move 3y to the left and -9 to the right and change their signs.
3y - 3y = - 9 + 9
0 = 0
All real numbers > many solutions
____________________________________
10x - 2 - 6x = 3x - 2 + x
4x - 2 = 4x - 2
Same as problem 6
___________________________________
4(x + 3)+ 2x = x - 8
4x + 12 + 2x = x - 8
6x + 12 = x - 8
Move x to the left and 12 to the right, then change their signs.
6x - x = -20
5x = -20
x = -4 > one solution
Willow is correct thank you so much I took one for the team and I’m so happy the answers are correct!!! Trust willow 100% if your with Connexus!
1.B
2.D
3.D
4.A
http://openstudy.com/updates/52a1e689e4b088e695c0cc86
If you answer comes out equal, then there is infinite solutions
3. 10x - 2 - 6x = 3x - 2 + x -- combine like terms 4x - 2 = 4x - 2 same thing here...it is gonna come out to 0 = 0 making it have infinite solutions
4. 4(x + 3) + 2x = x - 8 4x + 12 + 2x = x - 8 6x + 12 = x - 8 6x - x = -8 - 12 5x = - 20
x = -4
ONE SOLUTION
ze furtse fart that is correct by yht way...
willow is right :D (might me right only for connexus idk)
To solve these equations and determine the number of solutions, you need to simplify and solve for the variable.
Let's go through each equation step by step:
5. 2(x – 3) = 2x
To start, distribute the 2 to both terms inside the parentheses:
2 * x - 2 * 3 = 2x
This simplifies to:
2x - 6 = 2x
Now, subtract 2x from both sides to eliminate x on the right side:
2x - 2x - 6 = 2x - 2x
This simplifies to:
-6 = 0
But -6 does not equal 0, so this equation has no solutions.
Therefore, the answer is "no solutions."
6. 3(y – 3) = 2y – 9 + y
First, distribute the 3 to both terms inside the parentheses:
3 * y - 3 * 3 = 2y - 9 + y
Simplify:
3y - 9 = 2y - 9 + y
Combine like terms:
3y - 9 = 3y - 9
Now, subtract 3y from both sides:
3y - 3y - 9 = 3y - 3y - 9
This simplifies to:
-9 = -9
Since -9 equals -9, this equation has infinitely many solutions.
Therefore, the answer is "infinitely many solutions."
7. 10x – 2 – 6x = 3x – 2 + x
Combine like terms:
10x - 6x - 3x - x = -2 + 2
Simplify:
0 = 0
Since 0 equals 0, this equation has infinitely many solutions.
Therefore, the answer is "infinitely many solutions."
8. 4(x + 3) + 2x = x – 8
First, distribute the 4 to both terms inside the parentheses:
4 * (x + 3) + 2x = x - 8
Simplify:
4x + 12 + 2x = x - 8
Combine like terms:
6x + 12 = x - 8
Now, subtract x from both sides:
6x - x + 12 = x - x - 8
This simplifies to:
5x + 12 = -8
Finally, subtract 12 from both sides:
5x + 12 - 12 = -8 - 12
This simplifies to:
5x = -20
Divide both sides by 5 to solve for x:
(5x) / 5 = -20 / 5
This simplifies to:
x = -4
Since we found a specific value for x, this equation has one solution.
Therefore, the answer is "one solution."
To summarize:
5. No solution
6. Infinitely many solutions
7. Infinitely many solutions
8. One solution
Decide whether each equation has one solution, no solutions, or infinitely many solutions.
1. 2(x - 3) = 2x
A. one solution B. no solutions C. infinitely many solutions
2. 3(y - 3) = 2y - 9 + y
A. one solution B. no solutions C. infinitely many solutions
3. 10x - 2 - 6x = 3x - 2 + x
A. one solution B. no solutions C. infinitely many solutions 4. 4(x + 3) + 2x = x - 8 A. one solution B. no solutions C. infinitely many solutions
1. 2(x - 3) = 2x -- distribute through the parenthesis 2x - 6 = 2x -- add 6 to both sides 2x = 2x + 6 -- subtract 2x from both sides
2x - 2x = 6 0 = 6 (incorrect)
If you answer comes out not equal, then there is no solution
2. 3(y - 3) = 2y - 9 + y -- distribute and combine 3y - 9 = 3y - 9 -- subtract 3y 3y - 3y - 9 = - 9 -- add 9 3y - 3y = -9 + 9 0 = 0 (correct)