2x^2-12x+32=x^2 how would I solve this by factoring?

2x^2-12x+32=x^2

x^2-12x+32=0
(x-4)(x-8)

Use foil to check
x*x=X^2
-4*x=-4x
x*-8=-8x
-4*-8=32
Combine like terms
x^2-12x+32

Hope this helps

I had answered this for you 3 minutes after you first posted it.

http://www.jiskha.com/display.cgi?id=1388971076

Why would you post it again ?

To solve this equation by factoring, we will rearrange it into the form of a quadratic equation and then factor it.

Step 1: Move all the terms to one side of the equation to have it equal to zero:
2x^2 - 12x + 32 - x^2 = 0

Step 2: Combine like terms:
x^2 - 12x + 32 = 0

Step 3: Now, we need to find two numbers that multiply to give the constant term (32) and add up to give the coefficient of the x-term (-12). In this case, -4 and -8 satisfy these conditions since (-4)(-8) = 32 and -4 + (-8) = -12.

Step 4: Rewrite the middle term using the two numbers we found:
x^2 - 4x - 8x + 32 = 0

Step 5: Group the terms:
(x^2 - 4x) + (-8x + 32) = 0

Step 6: Factor by grouping:
x(x - 4) - 8(x - 4) = 0

Step 7: Now, we notice that we have a common factor of (x - 4):
(x - 4)(x - 8) = 0

Step 8: Apply the zero-product property:
(x - 4) = 0 or (x - 8) = 0

Step 9: Solve for x:
x = 4 or x = 8

Therefore, the solutions to the equation 2x^2 - 12x + 32 = x^2 are x = 4 and x = 8.