A car moving at 50 km/h skids 15m with locked brakes. show with locke brakes at 150 km/m the car will skid 135?
d =
d = (150/50)^2 * 15m = 135 m.
d = (150/50) * 15m = 135.
To determine how far a car will skid with locked brakes at a different initial speed, we can use the concept of kinetic energy.
The formula for kinetic energy is:
KE = (1/2) * m * v^2
where KE is the kinetic energy, m is the mass of the car, and v is the velocity of the car.
Assuming the mass of the car remains the same, we can consider the ratio of kinetic energy at different speeds:
KE1 / KE2 = (v1^2) / (v2^2)
To find the ratio of kinetic energy, we need to square the velocities:
(50 km/h)^2 / (150 km/h)^2
Now, we can calculate the ratio:
(50^2) / (150^2) = 2500 / 22500 = 1 / 9
So, at a speed of 150 km/h, the kinetic energy of the car will be 1/9th of the kinetic energy at a speed of 50 km/h.
Since the distance skidded is directly proportional to kinetic energy (assuming locked brakes), we can multiply the initial distance (15 m) by the ratio of kinetic energy to find the new distance:
New distance = (1/9) * 15 m = 135 / 9 = 15 m
Therefore, with locked brakes at 150 km/h, the car will skid 15 meters.