On Friday morning two clocks are correctly set at 6 a.m. One clock gains 1 minute every 2 hours. The other clock loses 1 minute every hour. When the real time is 10 p.m. that evening, the fast clock is ______ minutes ahead of the slow clock.
Please explain the answer
Thanks
I got 24 minutes because the clock is set at 6:00 am and there are 16 hours between 6 am and 10 pm fast clock gains 8 minutes and the slow clock loses 16 minutes
Am I right??????
I agree. 24 min. looks correct.
Yes, you are correct. To find the number of minutes the fast clock is ahead of the slow clock, you need to calculate the time difference between 6:00 am and 10:00 pm in both clocks. Let's break it down step by step.
First, calculate the time difference between 6:00 am and 10:00 pm. There are 16 hours between those two times. Since the clocks are initially set at 6:00 am, this means 16 hours have passed.
Next, consider the fast clock. You mentioned that it gains 1 minute every 2 hours. So, for the 16 hours that have passed, the fast clock would gain 8 minutes. This is because 16 divided by 2 equals 8.
Finally, look at the slow clock. You mentioned that it loses 1 minute every hour. So for the 16 hours that have passed, the slow clock would lose 16 minutes.
To find the difference between the clocks, subtract the time lost by the slow clock from the time gained by the fast clock: 8 minutes (gained by the fast clock) - 16 minutes (lost by the slow clock) = -8 minutes.
The negative value means that the slow clock is actually ahead of the fast clock by 8 minutes at 10:00 pm.
Therefore, the correct answer is that the fast clock is 8 minutes behind the slow clock at 10:00 pm.