A pound of grass seed covers 120 square feet of lawn.
how many pounds are needed to seed a lawn measuring 50 by 40 feet (2000sq ft)? is this answer is correct yes or no
2000/120 50/3 16 2/3
Yes.
Is this the correct question and solve this proportion 8/x=2/5 x=
2x=40 x=20
doknow
To find out how many pounds of grass seed are needed to cover a lawn measuring 2000 square feet, we can use the given information that 1 pound of grass seed covers 120 square feet of lawn.
First, divide the total area of the lawn (2000 square feet) by the coverage of 1 pound of grass seed (120 square feet). This can be done as follows:
2000 sq ft / 120 sq ft = 16.67
This calculation shows that approximately 16.67 pounds of grass seed would be needed to cover a lawn measuring 2000 square feet.
Now, let's check if the answer provided, 16 2/3, matches our calculation.
To convert the decimal number 16.67 to a mixed fraction, we can follow these steps:
1. Determine the whole number part. The whole number part of 16.67 is 16.
2. Determine the fraction part. The fraction part is obtained by subtracting the whole number part from the decimal number: 16.67 - 16 = 0.67.
3. Express the fraction part as a simplified fraction. Since 0.67 cannot be simplified any further, the fraction remains as 2/3.
4. Combine the whole number part and the fraction part to get the mixed fraction: 16 2/3.
Therefore, the answer provided, 16 2/3, is correct.