Determine the volume of diluted nitric acid D1.11g/ml, 19% hn03. That can be prepared by diluting with water 50ml of conc hn03 d= 1.42g/ml, 69.8%

I do not still understand how 183.68ml

I want you clear explain step by step for me.

ok, I guess you didn't like the volume ratio solution, so here is the general algebraic solution.

You have two solutions, one at 19% acid, and the water at 0% acid.

If you use x ml of water, the final solution will have (x+50)ml volume.

The amounts of acid in each component solution must add up to the amount of acid in the final solution. That is,

0.698*50 + 0.00*x = 0.19(x+50)
solve that and you get
x = 183.68