A person has the ability to jump with an initial speed of 6.0 m/s at an angle of 35 degree with the ground.
a. How long will the person be in the air?
b. How far horizontally will the person travel?
find the initial vertical velocity. 6sin35.
then, at the top, the final velocity is zero.
vf^2=vi^2+2gh solve for h. g=-9.8m/s^2