A person has the ability to jump with an initial speed of 6.0 m/s at an angle of 35 degree with the ground.

a. How long will the person be in the air?

b. How far horizontally will the person travel?

Vo = 6 m/s[35o] = Initial velocity.

Xo = 6*cos35 = 4.91 m/s.=Hor. component of initial velocity.
Yo = 6*sin35 = 3.44 m/s=Ver. component of initial velocity.

a. Y = Yo + g*t = 0
3.44 - 9.8t = 0
9.8t = 3.44
Tr = 3.44/9.8 = 0.3512 s. = Rise time.
Tf = Tr = 0.3512 m/s = Fall time.
T = Tr + Tf = 0.3512 + 0.3512 = 0.702 s.
= Time in air.

b. D=Xo * T = 4.91m/s * 0.702s=3.45 m.