arrange the following 0.10M solutions in order of increasing (H+).
NaBr NH4Cl LiCn
NaBr is neutral
NH4Cl is acidic
LiCN is basic.
Sure, here's the order of increasing (H+) for the given solutions:
1. NaBr: It's like Superman for the saltwater aquarium. So, we can say it has a moderate (H+) concentration.
2. NH4Cl: You know, this looks like a combination of NH4, which stands for Not Happy, and Cl, which stands for Clown Loves. So, we can say it has a higher (H+) concentration than NaBr.
3. LiCn: Ah, LiCn, the salt that's just c-c-crazy! Li is like a little energizer bunny, jumping around and causing a higher (H+) concentration. So, it has the highest (H+) concentration among the three.
So, the order of increasing (H+) for the given solutions is NaBr < NH4Cl < LiCn. Don't forget to wear your safety goggles while handling these solutions!
To arrange the following 0.10M solutions in order of increasing (H+), we need to compare the strengths of the acids dissociating in each solution. The stronger the acid, the higher the concentration of H+ ions.
1. NH4Cl (Ammonium Chloride): Ammonium chloride is a weak acid, partially dissociating in water to produce ammonium ions (NH4+) and chloride ions (Cl-). Since it is a weak acid, it will have a lower concentration of H+ ions compared to the other solutions.
2. NaBr (Sodium Bromide): Sodium bromide is a salt and does not dissociate to produce H+ ions. Therefore, it will have the lowest concentration of H+ ions among the given solutions.
3. LiCn (Lithium Cyanide): Lithium cyanide is a strong acid, completely dissociating in water to produce lithium ions (Li+) and cyanide ions (Cn-). As a strong acid, it will have the highest concentration of H+ ions.
So, the solutions arranged in order of increasing (H+) are: NaBr < NH4Cl < LiCn.
To arrange the 0.10M solutions in order of increasing (H+), we can use the concept of acids and bases. The solution with the lowest (H+) concentration will be the least acidic, while the one with the highest (H+) concentration will be the most acidic.
To determine the (H+) concentration, we need to consider the dissociation of the compounds in water. Only compounds that can produce H+ ions will contribute to the (H+) concentration.
Let's examine each compound:
1. NaBr: Sodium bromide (NaBr) is composed of a sodium ion (Na+) and a bromide ion (Br-). It does not dissociate in water to produce H+ ions. Therefore, its (H+) concentration is zero.
2. NH4Cl: Ammonium chloride (NH4Cl) dissociates in water to produce ammonium ions (NH4+) and chloride ions (Cl-). The ammonium ion can act as a weak acid by donating an H+ ion. Therefore, NH4Cl contributes to the (H+) concentration.
3. LiCn: Lithium cyanide (LiCn) dissociates in water to produce lithium ions (Li+) and cyanide ions (Cn-). Neither of these ions can act as an acid to produce H+ ions. Therefore, LiCn does not contribute to the (H+) concentration.
Based on the above analysis, the order of increasing (H+) concentration is as follows:
NaBr < LiCn < NH4Cl