algebra
posted by bowershe .
what is the graph of the equation? y=x^2 4x + 3

Parabola
x = b/2a
x= 4/2 = 2
f(2) = (2)^2 4(2) + 3
= 48 + 3 = 1
vertex (2,1)
0 = (x1)(x3)
x = 1, 3
(1, 0), (3,0)
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