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Logx16=-2 how do you solve?
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Logx16=-2 how do you solve this?
Top answer:
the first one is simple, logx16=2 .... x becomes the base and the 2 becomes the exponent there fore
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Logx16=-2 how do you solve?
Top answer:
x^-2 = 16 x^2 = 1/16 x = 1/4 since x^(log<sub>x</sub> n) = n
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Logx16=-2
Top answer:
Logx 16 = -2. x^-2 = 16 1/x^2 = 16 16x^2 = 1 x^2 = 1/16 x = 1/4.
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I will be happy to critique your work. To solve for x, combine the terms that include x on one side
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