geometry
posted by anabelle .
mrs. sally needed to build a triangular platform in the shape of an isosceles right triangle. the legs of the triangle are 6"long
how long was the base side of the triangular platform?
she also made well panels for the show that were 4" wide. how many wall panels would fit along the base side of the platform?
about how many inches of the base side of the platform will not have a wall?

c^2 = a^2 + b^2
c^2 = 6^2 + 6^2 = 72
c = 8.49 Ft. = 101.82 In.
101.82/4 = 25.46 or 25 Wall panels.
0.46 * 4 = 1.8 Inches.
.
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