Multiple choice question that's hard to figure out and understand.(information provided)
Ten members of a fraternity take a statistics course. Here are their scores on the first exam in the course: 61,74,47,60,62,63,65,79,55,85.
The question states: In all, 135 students too the exam. The third quartile for all 135 scores was 69. How many students had scores higher than 69? a. 34, b.67, c.69 and d.101
well, 3/4 of the scores were below 69.
That leaves 1/4 above. What's 1/4 of 135?
To find the number of students who had scores higher than 69, we need to determine the position of the third quartile within the entire set of scores.
Step 1: Sort the scores in ascending order from the provided data: 47, 55, 60, 61, 62, 63, 65, 74, 79, 85.
Step 2: Calculate the position of the third quartile. The third quartile divides the data into two halves, so it is located at the 75th percentile. The 75th percentile can be calculated as (75/100) * (n + 1), where n is the total number of scores. In this case, n = 135, so the 75th percentile is (75/100) * (135 + 1) = 101.25.
Step 3: Identify the number of students who had scores higher than 69. Since the 75th percentile is 101.25, it means that there are 101 students with scores lower than or equal to 69. Therefore, the number of students with scores higher than 69 is 135 (total students) - 101 (students with scores lower than or equal to 69) = 34.
Therefore, the correct answer is a. 34.