Q3:
In the combustion reaction of 149g of propane(C3H8) with excess oxygen, what volume of carbon dioxide(CO2) is produced at STP?
(note: balance the reaction first)
C3H8 + O2 3CO2 + H2O
C3H8 + 5O2 3CO2 + 4H2O
mols C3H8 = grams/molar mass
Using the coefficients in the balanced equation, convert mols C2H8 to mols CO2.
Now convert mols CO2 to L remembering that 1 mol occupies 22.4 L OR you can use PV = nRT and solve for V in L../
Df
To find the volume of carbon dioxide (CO2) produced at STP, we need to follow these steps:
Step 1: Balance the equation.
The balanced equation for the combustion of propane is:
C3H8 + 5O2 -> 3CO2 + 4H2O
Step 2: Calculate the number of moles of propane (C3H8).
To calculate the number of moles, we need to divide the given mass (149g) by the molar mass of propane (C3H8).
The molar mass of carbon (C) = 12.01 g/mol
The molar mass of hydrogen (H) = 1.008 g/mol
Molar mass of propane (C3H8) = (3 * molar mass of carbon) + (8 * molar mass of hydrogen)
= (3 * 12.01) + (8 * 1.008)
= 36.03 + 8.064
= 44.094 g/mol
Number of moles of propane = Mass of propane / Molar mass of propane
= 149g / 44.094 g/mol
= 3.38 mol
Step 3: Use the mole ratio to determine the number of moles of carbon dioxide.
According to the balanced equation, the mole ratio between propane and carbon dioxide is 1:3. Therefore, for every 1 mole of propane, 3 moles of carbon dioxide are produced.
Number of moles of carbon dioxide = Number of moles of propane * Mole ratio
= 3.38 mol * 3
= 10.14 mol
Step 4: Convert moles to volume at STP.
At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters.
Volume of carbon dioxide at STP = Number of moles of carbon dioxide * Volume per mole
= 10.14 mol * 22.4 L/mol
= 227.18 L
Therefore, the volume of carbon dioxide produced at STP is 227.18 L.
To find the volume of carbon dioxide (CO2) produced in the combustion reaction of propane (C3H8), we need to follow a few steps:
Step 1: Balance the chemical equation
The given equation is:
C3H8 + O2 -> 3CO2 + H2O
The equation is already balanced as it is written. There are 3 carbon dioxide (CO2) molecules produced for every 1 propane (C3H8) molecule.
Step 2: Convert the mass of propane to moles
Given:
Mass of propane (C3H8) = 149g
Molar mass of propane (C3H8) = 44.1 g/mol
To convert the mass of propane to moles, we use the formula:
Number of moles = (Mass of substance) / (Molar mass)
Number of moles of propane = 149g / 44.1 g/mol
Step 3: Determine the mole ratio
From the balanced equation, we can see that the mole ratio between propane (C3H8) and carbon dioxide (CO2) is 1:3. This means that for every 1 mole of propane, 3 moles of carbon dioxide are produced.
Step 4: Calculate the moles of carbon dioxide produced
To find the moles of carbon dioxide produced, we multiply the number of moles of propane by the mole ratio.
Moles of carbon dioxide = Number of moles of propane x Mole ratio
Moles of carbon dioxide = (Number of moles of propane) x 3
Step 5: Convert moles of carbon dioxide to volume at STP
At STP (Standard Temperature and Pressure), 1 mole of any ideal gas occupies 22.4 liters.
Volume of carbon dioxide = Moles of carbon dioxide x 22.4 L/mol
By following these steps,
1. Balance the chemical equation.
2. Convert the mass of propane to moles.
3. Determine the mole ratio.
4. Calculate the moles of carbon dioxide produced.
5. Convert moles of carbon dioxide to volume at STP.
You will be able to find the volume of carbon dioxide produced at STP in this combustion reaction.