write the equation in standard form:

2x^2-12x+5

I don't see any equation.

x^2-x+6=3

To write the quadratic equation 2x^2 - 12x + 5 in standard form, we need to rearrange the equation so that the terms are in order of decreasing degree. The standard form of a quadratic equation is Ax^2 + Bx + C = 0, where A, B, and C are constants.

Let's start by rearranging the equation:

2x^2 - 12x + 5

First, let's deal with the quadratic term, 2x^2. The coefficient of the quadratic term is already in the correct form, so we can write:

2x^2

Next, let's move on to the linear term, -12x. The coefficient -12 is the coefficient we want for the linear term, but we need to make sure it is multiplied by the variable x. We can achieve this by factoring out the common factor of 2 from the coefficient -12. By dividing -12 by 2, we get -6:

-12x = 2(-6)x = -12x

Now we have:

2x^2 - 12x

Finally, let's deal with the constant term, 5. To write it in standard form, we place it as the last term:

2x^2 - 12x + 5

Therefore, the quadratic equation 2x^2 - 12x + 5 in standard form is:

2x^2 - 12x + 5 = 0