A yoyo of mass m=2 kg and moment of inertia ICM=0.04 kg m2 consists of two solid disks of radius R=0.2 m, connected by a central spindle of radius r=0.15 m and negligible mass. A light string is coiled around the central spindle. The yoyo is placed upright on a flat rough surface and the string is pulled with a horizontal force F=12 N, and the yoyo rolls without slipping.

(a) What is the x-component of the acceleration of the center of mass of the yoyo? (in m/s2)

a=

unanswered
(b) What is the x-component of the friction force? (in N)

f=

a=F.(R+r)/(I/R+m.R)=7

f=F-m.a =-2 BUT you write 2 (without the minus (-) sing)

Shouldn't the acceleration be less than 6 m/s^2? The yoyo should not accelerate more than what is provided by the 12N force or a(max)= F/m = 12/2 = 6 m/s^2 ?

To solve this problem, let's break it down step by step:

Step 1: Find the torque generated by the applied force:
Since the yoyo is rolling without slipping, the applied force F will cause a torque.

The torque (τ) is given by the formula: τ = Iα

Here, I is the moment of inertia of the yoyo (ICM) and α is the angular acceleration of the yoyo.

Given ICM = 0.04 kg m^2, we can use this value to find the torque.

Step 2: Find the angular acceleration:
To find the angular acceleration, we can use Newton's second law for rotation:

τ = Iα

Where τ is the torque and α is the angular acceleration.

Since the torque (τ) is caused by the applied force F and the radius r, we can write:

τ = F * r

Substituting the values, τ = 12 N * 0.15 m = 1.8 Nm

Now we can solve for α:

1.8 Nm = 0.04 kg m^2 * α

α = (1.8 Nm) / (0.04 kg m^2) = 45 rad/s^2

Step 3: Find the linear acceleration:
The linear acceleration (a) of the center of mass of the yoyo can be found using the formula:

a = α * R

Where α is the angular acceleration and R is the radius of the yoyo.

Given α = 45 rad/s^2 and R = 0.2 m, we can calculate the linear acceleration:

a = 45 rad/s^2 * 0.2 m = 9 m/s^2

So, the x-component of the acceleration of the center of mass of the yoyo is 9 m/s^2.

Answer to (a): a = 9 m/s^2

Step 4: Find the x-component of the friction force:
The friction force (f) can be calculated using the equation:

f = μ * N

Where μ is the coefficient of friction and N is the normal force.

In this case, since the yoyo is placed on a flat rough surface, there is no vertical acceleration, and the normal force (N) is equal to the weight (mg) of the yoyo.

Given the mass m = 2 kg, we can calculate the normal force:

N = mg = 2 kg * 9.8 m/s^2 = 19.6 N

Now we need to find the coefficient of friction (μ). Since the question doesn't provide this information, we cannot determine the value of μ and solve for the friction force (f).

Answer to (b): The x-component of the friction force (f) cannot be determined without the coefficient of friction.

So, the answer to (b) is unknown without additional information.