Solve this substitution:

2x-5x=-8
-3x-2y=-26

Did you mean 2x - 5y = -8 for the first one ?

I will assume that is what you meant:

Personally I would not use substitution, but ....

from the 2nd
26-3x = 2y
(26-3x)/2 = y

into the 1st:
2x - 5(26-3x)/2 = -8
times 2 to get rid of that fraction ...
4x - 5(26-3x) = -16
4x - 130 + 15x = -16
19x = 114
x = 6
then y = (26-18)/2 = 4

x = 6 , y = 4

To solve this system of equations by substitution, we'll follow the steps below:

Step 1: Rewrite one of the equations in terms of one variable.
Step 2: Substitute the value of the expression from Step 1 into the other equation.
Step 3: Solve the resulting equation.
Step 4: Substitute the value of one variable into either of the original equations to solve for the second variable.

Let's start with the first equation:
2x - 5x = -8

Step 1: Combine like terms:
-3x = -8

Step 2: Solve for x by dividing both sides by -3:
x = -8 / -3
x = 8/3

Now that we have the value of x, we can substitute it into the second equation:
-3(8/3) - 2y = -26

Step 3: Simplify the equation:
-8 - 2y = -26

Step 4: Solve for y by moving -8 to the other side:
-2y = -26 + 8
-2y = -18

Divide by -2 to isolate y:
y = -18 / -2
y = 9

Therefore, the solution to the system of equations is x = 8/3 and y = 9.