Math
posted by Hanad .
Solve this substitution:
2x5x=8
3x2y=26

Did you mean 2x  5y = 8 for the first one ?
I will assume that is what you meant:
Personally I would not use substitution, but ....
from the 2nd
263x = 2y
(263x)/2 = y
into the 1st:
2x  5(263x)/2 = 8
times 2 to get rid of that fraction ...
4x  5(263x) = 16
4x  130 + 15x = 16
19x = 114
x = 6
then y = (2618)/2 = 4
x = 6 , y = 4