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A 5 inch by 8 inch rectangle is enlarged to a similar rectangle whose smallest side measures 9 inches. What is the length in inches of the diagonal of the enlarged rectangle?

  • Math -

    D1/D2 = 5/9

    D1 = √(5^2 + 8^2) = √89

    so √89/D2 = 5/9
    5D2 = 9√89
    D2 = 9√89/5

    notice that the diagonal increased by a factor of 9/5 or the same as the increase in the sides.

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