What are the zeroes of y = x2 – 2x – 15?

–3, –5
3, 5
–3, 5
3, –5

You must mean

y = x^2 - 2x - 15 , note how we show exponents.
=(x-5)(x+3)
so the zeros are -3 and 5

zeroes?

y=0=(x-5)(x+3)
x=5, or x=-3

Thank guys :)

To find the zeroes of a quadratic equation, we need to solve for x when y is equal to zero. In the given equation, y = x^2 – 2x – 15.

Step 1: Set y = 0.
0 = x^2 – 2x – 15

Step 2: Factorize the quadratic equation.
We need to find two numbers whose product is -15 and whose sum is -2. The numbers -3 and 5 satisfy these requirements.
0 = (x - 3)(x + 5)

Step 3: Set each factor equal to zero.
x - 3 = 0 or x + 5 = 0

Step 4: Solve for x.
For x - 3 = 0, adding 3 to both sides gives us x = 3.
For x + 5 = 0, subtracting 5 from both sides gives us x = -5.

Therefore, the zeroes of y = x^2 – 2x – 15 are x = -3 and x = 5.

So, the correct answer is option C: -3, 5.