Calculus volume stuff
posted by Roni .
Find the volume of the solid obtained by rotating the region bounded
y = 16 x and y = 2 x^2 about y =0
Find the volume of the solid obtained by rotating the region bounded about the xaxis by y=4x^2, x =1, and y = 0
Find the volume of the solid generated by rotating the region bounded by
y = \sin^2(x) and y = 0
between 0 and pi about the xaxis

washers: v=∫[0,8] π(R^2r^2) dx
where R=16x and r=2x^2
= 2621454/15 π
shells: v=∫[0,128] 2πrh dy
where r=y and h=√(y/2)y/16
= 2621454/15 π
Can you set up the other integrals?