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A dock worker loading crates on a ship finds that a 29 kg crate, initially at rest on a horizontal surface, requires a 90 N horizontal force to set it in motion. However, after the crate is in motion, a horizontal force of 60 N is required to keep it moving with a constant speed. The acceleration of gravity is 9.8 m/s^2
Find the coefficient of static friction be- tween the crate and floor.

  • physics -

    Fc = m*g = 29kg * 9.8N/kg = 284.2 N. =
    Force of crate.

    Fap-Fs = m*a
    90-u*Fc = m*0
    90 - u*284.2 = 0
    u*284.2 = 90
    us = 0.317

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