A 4.06m long organ pipe is open on both ends.
A)Find its fundamental frequency.
B)Find its first three overtone frequencies
To find the fundamental frequency of an organ pipe that is open on both ends, you can use the formula:
f = v / (2L)
Where:
f = frequency of the pipe (fundamental frequency)
v = speed of sound in air (approximately 343 m/s at room temperature)
L = length of the pipe
A) Calculating the fundamental frequency:
f = 343 / (2 * 4.06)
≈ 42 Hz
So, the fundamental frequency of the organ pipe is approximately 42 Hz.
Now, to find the first three overtone frequencies, you can use the formula:
fn = nf
Where:
fn = frequency of the nth overtone
f = fundamental frequency
B) Calculating the first three overtone frequencies:
1st overtone frequency (n = 1):
f1 = 1 * 42
= 42 Hz
2nd overtone frequency (n = 2):
f2 = 2 * 42
= 84 Hz
3rd overtone frequency (n = 3):
f3 = 3 * 42
= 126 Hz
Therefore, the first three overtone frequencies of the organ pipe are approximately 42 Hz, 84 Hz, and 126 Hz.