a couple has just learned that their daughter has hemophilia. they alredy have a son who does not have the disease.what are the genotypes of the couple

Hemophilia is an X-linked recessive genetic disorder, which means it is usually passed on from carrier mothers to their sons. In this case, we know that the couple has a daughter with hemophilia and a son without the disease. Based on this information, we can determine the most probable genotypes of the couple.

Let's assign the following:

- X^h as the allele for hemophilia
- Y as the allele for a normal condition

Knowing that the daughter has hemophilia, she must have inherited an X^h allele from one of her parents. Since the son does not have the disease, we can conclude that he received a normal allele (Y) from his parents.

Given that the father cannot pass on an X^h allele to his son, it is most likely that the mother is a carrier for hemophilia. Carriers are usually heterozygous females with one normal allele (X^h X) and one hemophilia allele (X^h X^h).

Therefore, we can deduce that the genotypes of the couple are as follows:

- The mother is a carrier: X^h X^h
- The father is unaffected: X Y

To determine the genotypes of the couple, we need to understand how hemophilia is inherited. Hemophilia is a sex-linked recessive genetic disorder that is carried on the X chromosome.

Since the couple has a daughter with hemophilia, it means that the mother is either a carrier of the defective gene or affected by the disease herself, and the father does not carry or have the defective gene. We can then make the following assumptions:

1. The daughter inherited the defective gene from her mother because her father does not have the disease.
2. The mother must have at least one copy of the defective gene to pass it onto her daughter.

Based on these assumptions, we can deduce the following genotypes:

- The mother must be either a carrier (XhX) or affected (XhXh) by the hemophilia gene. (X represents a normal X chromosome, and Xh represents a chromosome with the hemophilia gene.)
- The father must have a normal X chromosome (X).

Since the son does not have hemophilia, we can conclude that he has received a normal X chromosome from his mother, which means she must be a carrier of the defective gene (XhX).

Therefore, the genotypes of the couple are:

- The mother: XhX (carries the hemophilia gene)
- The father: X (does not carry the hemophilia gene)

I assume you only need to determine the sex chromosomes.

The daughter has XX sex chromosomes. Since she has hemophilia, a recessive gene on the X chromosome, she must have inherited the hemophilia from both parents. However, since the son also receives an X chromosome from mom, it must be for normal blood clotting.

With this information, you should be able to figure the answer.