posted by dinah .
6.01-L cylinder contains 1.25 mol of gas A and 4.54 mol of gas B, at a temperature of 32.8 °C. Calculate the partial pressure of each gas in the cylinder. Assume ideal gas I have work this question three time and can not get the rt answer
PV = nRT
p = nRT/V
pA = 1.25*0.08206*(273.2 + 32.8)/6.01 = 5.22
pB = same thing.
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