If point A is (-8,3) and point B is (-6,1) and slope is -1 what would the x and y intercepts be?

What would the equation be in standard form?

Given: A(-8,3), B(-6,1). m = -1

A(-8,3), P(x,y). m== -1.
m = (y-3)/(x-(-8)) = -1
m = (y-3)/(x+8) = -1
Cross multiply:
y-3 = -1(x+8)
y-3 = -x-8
Eq: x + y = -5
Or x + y +5 = 0

Replace y with 0:
x + 0 = -5
X = -5 = X-intercept.

Replace X with 0:
0 + y = -5
Y = -5 = y-int.