Math
posted by Mindy .
Simplify 2a^2 b^3 (4a^2 + 3ab ab)
A.) 8a^4 b^5 + 3a^3 b^5  2a^3 b^4
B.) 8a^4 b^3 + 6a^3 b^5  2a^3 b^4
C.) 8a^4 b^3 + 6a^3 b^5 + 2a^3 b^4
D.) 8a^4 b^5 + 3a^3 b^5 + 2a^3 b^4
I'm guessing its A

2a^2 b^3 (4a^2 + 3ab ab)
Distribute to each:
2a^2 b^3 * 4a^2 = 8a^4 b^3
2a^2 b^3 * 3ab = 6a^3 b^4
2a^2 b^3 * (ab) = 2a^3 b^4
Adding them,
8a^4 b^3 + 6a^3 b^4 2a^3 b^4
= 8a^4 b^3 + 4a^3 b^4
Actually either there's no answer in the choices, or there is a typo. :3 
2a^2 b^3 (4a^2 + 3ab ab)
Nah, no b^5 term results
Perhaps you mean
2a^2 b^3 (4a^2 + 3ab^2 ab)
which is
8 a^4 b^3 + 6 a^3 b^5  2 a^3 b^4
which is B 
None of those b/c the 2nd b is b^4
It is
8a^4b^3 + 6a^3b^4  2^3b^4 
Thank you Damon the answer was B
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