IF point A is (3,8) and point B is -6,-4)and the slope is 4/3 what would the x and y intercepts be?

do you have answer choices?

No

see other problem

Hannah, you have had several related questions, and should be able to do these by now.

Once more ....
you slope is correct.

Here is a method that should work for you all the time
if you know the slope and a point
( let's pick the point (3,8) with slope 4/3

then (y-8)/(x-3) = 4/3
cross-multiply and your fractions disappear.
4x - 12 = 3y - 24
4x - 3y = -12
This equation is often called the "standard form" in some textbooks.

it is very easy to find the intercepts from that form .
let x = 0 (put your little pinkie over the x term, what have you got left ? ) y = 4
let y = 0 (put your little pinkie over the y term, and what is left ? ) x = -3

and there you go, you got your intercepts.

To find the x-intercept, we need to calculate the value of x when the y-coordinate is zero.

The slope-intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept. In this case, we know the slope is 4/3, so the equation of the line passing through points A and B is y = (4/3)x + b.

To calculate the y-intercept, we can substitute the coordinates of point A (3, 8) into the equation:

8 = (4/3)(3) + b

Simplifying, we have:

8 = 4 + b

Subtracting 4 from both sides, we get:

4 = b

So, the equation becomes:

y = (4/3)x + 4

To find the x-intercept, we set y equal to zero and solve for x:

0 = (4/3)x + 4

Subtracting 4 from both sides, we have:

-4 = (4/3)x

Dividing by (4/3), we get:

-4 / (4/3) = x

Simplifying, we have:

-12/4 = x

-3 = x

Therefore, the x-intercept is -3.

To find the y-intercept, we can look at the equation y = (4/3)x + 4. The y-intercept is the y-coordinate when x is zero.

Substituting x = 0 in the equation, we have:

y = (4/3)(0) + 4

Simplifying, we get:

y = 0 + 4

y = 4

Therefore, the y-intercept is 4.

In conclusion, the x-intercept is -3 and the y-intercept is 4.