I'm suppose to solve

log(3)-27=x

I get 3^x=-27

I can't go any father correct?

Logarithm of a negative number is imaginary. If you try plotting y = log x, you'll see that the x values are all positive and infinitely approaches zero.

So does that mean x=3? (so 3x3x3=27)

No, there is no solution, since log(any negative) is undefined.

For the equation to be true, you correctly stated that
3^x = -27

I suggest you look at the graph of
y = 3^x and see where the y value is -27.

http://www.wolframalpha.com/input/?i=plot+y+%3D+3%5Ex

Actually, you made a small mistake in your simplification. When solving the equation log(3) - 27 = x, you cannot directly convert it to 3^x = -27. Let's go through the correct way to solve it.

To solve the equation log(3) - 27 = x, we need to isolate x.

First, let's add 27 to both sides of the equation:
log(3) - 27 + 27 = x + 27

This simplifies to:
log(3) = x + 27

Now, to isolate x, let's subtract 27 from both sides:
log(3) - 27 = x + 27 - 27

This simplifies to:
log(3) - 27 = x

So, the solution to the equation log(3) - 27 = x is x = log(3) - 27.