Math #2
posted by Nicole .
If I had a math problem 2x^4 x y^4 x z^3 / 3x^2 x y^3 x z^4.
In simpler terms it would look like this:
2x^4 X y^4 X z^3

3x^2 X y^3 X z^4
When I tried to solve this I got 6x^2 X y^1 X 2^7. Am I correct? If not could you please help me on how to solve it.

Nope. The coefficients just divide normally: 2/3
x^4/x^2 = x^2
y^4/y^3 = y^1
z^3/z^4 = z^7
so, you wind up with
2/3 x^2 y^1 z^7, or
2x^2

3yz^7
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