If x=(2/y^2)+2,what is the value of y in terms of x ?
please answer and explain
x = (2/y^2) + 2
Place the 2 from the right side to the left side.
x - 2 = 2 / y^2
Multiply both sides by y^2.
(x - 2) * y^2 = (2 / y^2) * y^2
(x - 2) * y^2 = 2
Divide 2 from the right side by x - 2 to isolate all terms with y.
y^2 = 2 / (x - 2)
Finally, get the squareroot.
y = sqrt( 2 / (x-2) )
Hope this helps :3
I like your answer and explain . step by step, now I understand how to do that.thank you, Jai
To find the value of y in terms of x, we can rearrange the equation:
x = (2/y^2) + 2
Subtract 2 from both sides:
x - 2 = 2/y^2
Next, invert both sides of the equation:
1/(x - 2) = y^2/2
To isolate y, we take the square root of both sides:
√(1/(x - 2)) = √(y^2/2)
Simplifying further:
± √(1/(x - 2)) = ±(y/√2)
Thus, in terms of x, y can be expressed as:
y = ± √(2/(x - 2))
Note that since we introduced a square root, y can have both positive and negative values.