A support wire runs from the top of a tower to the ground. If the tower is 1200 feet tall and the wire is attached to the ground 500 feet away from the tower, how long is the support wire?
A^2 + B^2 = C ^2
(500)^2 + (1200)^2 = C^2
1690000 = C^2
C = 1300 ft
Thank you!
This a job for the Pythagorean Theorem since the wire forms the hypotenuse of a right-angle triangle.
1200^2 + 500^2 = c^2
1,440,440 + 250,000 = c^2
1,690,440 = c^2
1,300.17 = c
where did that .17 come from?
This is just a scaled-up 5-12-13 triangle
Just to note: 1200^2 is not 1440440, it is 1440000, since 12^2 = 144
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Determine whether the function is linear. If so, give the slope and y-intercept of the function's graph.
f(x)=6x−3x+1
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Determine whether the function is linear. If so, give the slope and y-intercept of the function's graph.
f(x)=6x−3x+1
To find the length of the support wire, we can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides.
In this case, the tower forms the vertical side of the right triangle, the wire forms the hypotenuse, and the distance from the tower to the ground forms the horizontal side. Let's call the length of the support wire 'x'.
Using the Pythagorean theorem, we can write the equation:
x^2 = 1200^2 + 500^2
To solve for x, we square both sides of the equation:
x = √(1200^2 + 500^2)
Calculating the right side of the equation:
x = √(1440000 + 250000)
x = √(1690000)
x ≈ 1300.41
Therefore, the length of the support wire is approximately 1300.41 feet.