# Chemistry

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How many milliliters of 0.200M HCl can react with 3.25g CaCO3?

• Chemistry -

balance the equation:
2HCl + CaCO3 >> CO2 + H2O + CaCl2

figure the moles of calcium carbonate:
3.25/molmassCaCO3

then you must need twice that of acid.

2*3.25/molmassCaCO3 = volume*.2M

solvefor volume in liters. change to milliliters.

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