# TO ANY MATH HELPERS

posted by .

Pleeeese help!

Use the substitution method to solve each linear system:

-x+3y+1=0
3x-y+1=0

4x-3y=-13
-2x+y=4

• TO ANY MATH HELPERS -

1)

x= -.5
y= -.5

2)

x=.5
y=5

• TO ANY MATH HELPERS -

1.
from the 1st equation: x = 3y+1
into the 2nd:
3(3y+1) - y +1 = 0
9y + 3 - y +1 = 0
8y = -4
y = -1/2
sub into 2nd:
3x - (-1/2) + 1 = 0
3x = -3/2
x = -1/2

Do #2 the same way
from the 2nd: y = 2x+4
etc

(Just stating the answers is not acceptable and serves no purpose)

• TO ANY MATH HELPERS -

Oh thank you to both helpers!!! I have understood how to do it now:)

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