Algebra
posted by Anju .
Of twocar families in a small city, 88% remain twocar families in the following year and 12% become onecar families in the following year. Of onecar families, 72% remain onecar families and 28% become twocar families. Suppose these trends continue for a few years. At present, 4800 families have one car and 4200 families have two cars.
Find the numbers of onecar familes and two car families two years from now.

Algebra 
Reiny
I assume you are learning about Markov's chains in the study of matrices
end of year 1:
[4200 4800] x
.88 .12
.72 .28
=
[7152 1848]
end of year 2
[7152 1848]
.88 .12
.72 .28
=
[7624.32 1375.68]
I am not absolutely sure if I have the correct order, haven't done this kind of math in almost 20 years.
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