1. What is the vertex of each of these parabolas?
a. y = (x –7)2 +4 b. y = 3(x + 7)2 – 4
to type an exponent, we use the ^
a) y = (x-7)^2 + 4
vertex is (7,4)
you must learn the pattern to pick out the vertex from that standard form
if y = a(x-p)^2 + q, the vertex is (p,q)
(notice the x value is opposite of p, the y value is the same as q )
x greater than 1
To find the vertex of a parabola in the form y = a(x - h)^2 + k, where (h, k) represents the vertex, we need to identify the values of h and k.
a. For the equation y = (x – 7)^2 + 4, the vertex form is y = a(x - h)^2 + k.
Comparing it to the given equation, we see that h = 7 and k = 4. The vertex is located at (7, 4).
b. For the equation y = 3(x + 7)^2 - 4, again, we can identify the values of h and k using the vertex form.
In this case, h = -7 and k = -4. Thus, the vertex is located at (-7, -4).