Write an isomer of structure for a), b) and c) and name them.
*(N.B- ! rep. a bond)
a) CH3
!
CH3-CH2-C-CH2-CH3
!
CH3
CH3
!
b) CH3-CH2-CH-CH-C(TRIPLE BOND)CH
!
CH2
!
CH3
c) 3,3,4-trimethyl-1-pentene
disregard this question. I posted it in a better form further up.
To draw the isomer structures, you can use the basic principle of organic chemistry, which is the arrangement of atoms. By analyzing the given structures, we can determine the isomers and draw their structures.
a) Isomer structure:
To generate an isomer for the given structure, we need to rearrange the atoms while maintaining the same molecular formula. In this case, we can rearrange the carbon branches connected to the central carbon atom. Here's an isomer structure of compound a:
CH3
!
CH3-C-CH2-CH2-CH3
!
CH3
The name of this isomer is 2-methylpentane.
b) Isomer structure:
For the given structure, we can generate an isomer by rearranging the carbon-carbon triple bond. Here's an isomer structure of compound b:
CH3-CH2-CH-CH(CH3)-CH3
!
CH2
!
CH3
The name of this isomer is 3-methyl-2-pentyne.
c) Compound c:
The given compound, 3,3,4-trimethyl-1-pentene, is already a named compound. The name tells us the position of the methyl groups (3,3,4), the number of methyl groups (trimethyl), and the presence of a double bond (1-pentene).
I hope this explanation helps you understand how to generate isomer structures and name them based on the given information.