Algebra
posted by Stone .
Information is given about a polynomial f(x) whose coefficients are real numbers. Find the remaining zeros of f.
Degree 5; zeros: 9, 3+5i, 9i

complex roots always come in conjugate pairs
so roots are 9, 3 ± 5i, ± 9i
fo f(x) = (x9)(x35i)(x3+5i)(x+9i)x9i)
= (x9)(x^2  6x + 34)(x^2 + 91)
expand if need be
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