Post a New Question

PHYICS

posted by .

One end of a meter stick is pinned to a table, so the stick can rotate freely in a plane parallel to the tabletop. Two forces, both parallel to the tabletop, are applied to the stick in such a way that the net torque is zero. The first force has a magnitude of 2.00 N and is applied perpendicular to the length of the stick at the free end. The second force has a magnitude of 6.00 N and acts at a 60.2o angle with respect to the length of the stick. Where along the stick is the 6.00-N force applied? Express this distance with respect to the end of the stick that is pinned.

  • PHYICS -

    F1L1-F2L2=0
    L2= dsin(theta)
    so,
    d=(F1L1)/(F2sin(theta)
    d= (2x1)/(6sin(60.2))

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question