# PHYICS

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One end of a meter stick is pinned to a table, so the stick can rotate freely in a plane parallel to the tabletop. Two forces, both parallel to the tabletop, are applied to the stick in such a way that the net torque is zero. The first force has a magnitude of 2.00 N and is applied perpendicular to the length of the stick at the free end. The second force has a magnitude of 6.00 N and acts at a 60.2o angle with respect to the length of the stick. Where along the stick is the 6.00-N force applied? Express this distance with respect to the end of the stick that is pinned.

• PHYICS -

F1L1-F2L2=0
L2= dsin(theta)
so,
d=(F1L1)/(F2sin(theta)
d= (2x1)/(6sin(60.2))

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