Draw the compound that would produce 4-ethyl-3-hexanol in the presence of a nickel catalyst and hydrogen.
To draw the compound that would produce 4-ethyl-3-hexanol in the presence of a nickel catalyst and hydrogen, we need to start with the precursors involved in the reaction.
First, we have "ethyl," which refers to an ethyl group, denoted as:
CH3CH2-
Next, we have "hexanol," which indicates a six-carbon alcohol. Since we specifically want 4-ethyl-3-hexanol, we need to account for the ethyl group on the fourth carbon and the hydroxyl group on the third carbon of the hexanol chain.
The basic structure of hexanol is:
CH3CH2CH2CH2CH2CH2OH
Now, to incorporate the ethyl group on the fourth carbon, we add the ethyl group "CH3CH2-" to the fourth carbon of the hexanol chain. The final compound would look like this:
CH3CH2CH2CH2CH(CH3)CH2OH
This is the compound that would be produced when the reactant undergoes hydrogenation in the presence of a nickel catalyst and hydrogen.