a number is less than one fourth of the sum of three times the number and four.
can someone please explain to me how they got this answer and can someone please show me each step.
Two time the sun of à number and four is no more than three times the sum of the number and seven decreased by four
To solve this problem, let's break it down step by step:
Let's represent the unknown number as "x".
Step 1: "A number is less than one-fourth of the sum of three times the number and four."
This can be translated into an equation as follows:
x < (1/4)(3x + 4)
Step 2: Distribute the 1/4 to the terms inside the parentheses:
x < (3/4)x + 1
Step 3: Move all terms containing "x" to one side of the inequality and constants to the other side:
x - (3/4)x < 1
Simplifying this equation gives:
(1/4)x < 1
Step 4: Multiply both sides of the inequality by 4 to isolate "x":
4 * (1/4)x < 4 * 1
x < 4
Therefore, the answer is x < 4. This means that any number less than 4 satisfies the original statement.
a number is less than one fourth of the sum of three times the number and four.
n < (3n+4)/4