What volume of ammonia gas will be produced when 6.52 L of hydrogen react completely?
2N2 + 3H2 -> 2NH3
When dealing with gases one may use L as if they were mols.
6.52 L H2 x (2 mol NH3/3 mols H2) = 6.52 x 2/3 = ?
2N2 + 3H2 -> 2NH3
6.52 L H2 x (2 mol NH3/3 mols H2) = 6.52 x 2/3 = ?