What is the charge of a bare Magnesium nucleus (no electrons, just the protons and neutrons) in Coulombs?

1.92*10^(-18)

Mg loses two electrons when it ionizes,becoming a +2e charge.

that is 2* charge on one electron. or 2e

Now, losing all the electrons, would be most unusual in our universe. If it happened, Mg loses all 12 electrons, and its charge would be +12e

But, I have never heard of a "bare" Magnesium nucleus existing alone.

what is the value of e? 1.602176565(35)×10−19 coulombs.

The charge of a bare magnesium nucleus can be determined by the charge of its protons. Each proton has a positive charge of +1.6 x 10^-19 Coulombs.

To find the charge of the magnesium nucleus, we need to know the atomic number of magnesium, which is 12. This means that a magnesium atom typically has 12 protons in its nucleus.

So, to calculate the charge of a bare magnesium nucleus, we multiply the charge of a single proton (+1.6 x 10^-19 C) by the number of protons in the nucleus (12):

Charge of Magnesium nucleus = (Charge of a proton) x (Number of protons)
= (+1.6 x 10^-19 C) x (12)
= +1.92 x 10^-18 Coulombs

Therefore, the charge of a bare magnesium nucleus is approximately +1.92 x 10^-18 Coulombs.