On some strange planet you find that a 17.4 kg object falls downward 24.6 meters in 3.4 seconds. What is the magnitude of the acceleration due to gravity on this planet?
To find the magnitude of the acceleration due to gravity on this planet, we can use the formula:
Acceleration = (2 * Distance) / (Time^2)
We are given:
Distance = 24.6 meters
Time = 3.4 seconds
Substituting these values into the formula, we have:
Acceleration = (2 * 24.6) / (3.4^2)
Simplifying the expression:
Acceleration = 49.2 / 11.56
Calculating the value:
Acceleration = 4.25 m/s^2
Therefore, the magnitude of the acceleration due to gravity on this planet is approximately 4.25 m/s^2.
To find the magnitude of the acceleration due to gravity on this planet, we can use the equation of motion for free fall:
d = (1/2)gt^2
where d is the displacement, g is the acceleration due to gravity, and t is the time.
In this case, the displacement (d) is given as 24.6 meters, and the time (t) is given as 3.4 seconds.
By rearranging the equation, we can solve for the acceleration due to gravity (g):
g = (2d) / t^2
Substituting the values:
g = (2 * 24.6) / (3.4^2)
Calculating the expression:
g = 48.8 / 11.56
g ≈ 4.22 m/s^2
Therefore, the magnitude of the acceleration due to gravity on this planet is approximately 4.22 m/s^2.
d = 0.5g*t^2 = 24.6 m.
0.5g*3.4^2 = 24.6
Solve for g.