algebra

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could someone check my answers to these few questions?

"What is the equation of the line, in slope-intercept form, that goes through the point (-1, -8) with m = 3 ?"

here's my work:
y + 8 = -3(x + 1) [i put the values into the equation.]
y = -3x + 5 [i multiplied -3 by 1 and added 8 to both sides.]

is this right? my main question is whether or not i would add or subtract 8 in this situation. i know that y - (-8) is exactly the same as y + 8, so, in that case, would i subtract 8 from both sides?

  • algebra -

    y = mx + b

    -8 = (3)(-1) + b
    -8 = -3 + b
    -8 + 3 = -3 + 3 + b

    b = -5
    y = 3x -5

  • algebra -

    unfortunately, y = 3x -5 is not an answer. here are my option:

    A. y = -3x + 11
    B. y = -3x + 5
    C. y = -3x - 11
    D. y + 1 = -3(x + 8)

  • algebra -

    this is slope intercept form: y - y1 = m(x-x1)

  • algebra -

    oh wait nevermind, oops, that is not slope intercept form

  • algebra -

    (-1, -8)
    m = 3


    y -y1 = m (x -x1)

    y -(-8) = 3 ( x - (-1))
    y + 8 = 3(x + 1)

    y + 8 = 3x + 3

    y + 8 - 8 = 3x + 3 -8

    y = 3x -5

    Slope intercept form
    y = mx + b

  • algebra -

    The problem is the slope.

    All the options indicate a slope of -3, but you stated the slope to be +3

    Kuai's solution is correct according to the data supplied.

  • algebra -

    oops, sorry!

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