I got part a but part b I'm having trouble with I keep getting 56.2mL.
I'm not sure what the next step is really to find part b.
A. How would you prepare 250 mL of a 0.150 M solution of CoCl2 from solid CoCl2 and distilled water?
Dissolve 4.87 grams solid CoCl2 into enough water to make 250mL of solution using a volumetric flask.
b. Using the solution prepared in part a and distilled water, how would you prepare 100 mL of a 0.0600 M solution of CoCl2?
Measure mL of the 0.150 M CoCl2 solution using a volumetric pipet into a volumetric flask and add enough water to bring the solution level up to the line.
.150 to .06 is diluting it 150/6 times, or 25 tims. diluting something 25 times means 1 part base solution, adding 24 parts water.
you want 250ml, so one part is 10ml
take one part (10ml) of .150M, add 240ml of water, stir, and label.
I believe Mr. Pursley meant .150 to .06 is 15.0/6 = diluting 2.5 times. Just a typo.
To prepare 100 mL of a 0.0600 M solution of CoCl2 using the solution prepared in part a, follow these steps:
1. Calculate the amount of CoCl2 solution needed:
M1 * V1 = M2 * V2
where:
M1 = initial concentration in part a (0.150 M)
V1 = initial volume in part a (unknown)
M2 = desired concentration (0.0600 M)
V2 = desired final volume (100 mL)
Rearrange the formula to solve for V1:
V1 = (M2 * V2) / M1
2. Substitute the given values into the formula:
V1 = (0.0600 M * 100 mL) / 0.150 M
V1 = (6.00 mL) / 0.150 M
V1 = 40 mL
3. Measure 40 mL of the 0.150 M CoCl2 solution using a volumetric pipet.
4. Transfer the measured solution into a volumetric flask.
5. Add enough distilled water to bring the solution level up to the line on the volumetric flask.
By following these steps, you will be able to prepare 100 mL of a 0.0600 M solution of CoCl2 using the solution prepared in part a.
To determine part b, which involves preparing a 100 mL of a 0.0600 M solution of CoCl2, you can use a dilution formula. The formula for dilution is:
C1V1 = C2V2
Where:
C1 = Initial concentration
V1 = Initial volume
C2 = Final concentration
V2 = Final volume
In this case, the initial solution from part a has a concentration of 0.150 M and a volume of 250 mL. We need to prepare a final solution with a concentration of 0.0600 M and a volume of 100 mL.
Substituting the values into the dilution formula, we have:
(0.150 M)(V1) = (0.0600 M)(100 mL)
Let's solve for V1, which represents the volume of the initial solution needed.
V1 = (0.0600 M)(100 mL) / 0.150 M
V1 = (6.00 mmol)(100 mL) / 15.0 mmol
V1 = 600 mL / 15
V1 = 40 mL
Therefore, you need to measure 40 mL of the 0.150 M CoCl2 solution using a volumetric pipet. After that, add enough distilled water to bring the total solution volume up to 100 mL.