In addition to the Mg nucleus at x = 3 cm, another 3e charge is situated on the y-axis, 3cm away from the origin in the +y direction as shown below:

What is the magnitude of the Electric Field halfway between the Magnesium nucleus and the 3e charge on the y axis in N/C?

Distance between charges is d=sqrt{3²+3²} =4.24 cm

x=d/2 =4.24/2 =2.12 cm =0.0212 m
E=kq₁/x²-kq₂/x² =
=k12e/x²-k3e/x²=k9e/x²=
=9•10⁹•9•1.6•10⁻¹⁹/0.0212²=
=2.9•10⁻⁵ N/C

hai why is marked incorrect did u get green check on this question ?? and thx for support

What is the magnitude of the net electrostatic force a Boron nucleus would experience at the point halfway between the Magnesium nucleus and the 3e charge on the y axis in N?

3.84e-23

To find the magnitude of the electric field halfway between the magnesium nucleus and the 3e charge on the y-axis, we can use the principle of superposition.

The electric field at any point due to multiple charges is the vector sum of the electric fields produced by each charge individually. In this case, we have two charges: the magnesium nucleus and the 3e charge on the y-axis.

Step 1: Calculate the electric field due to the magnesium nucleus.
The electric field due to a point charge is given by Coulomb's law:
Electric field due to a point charge (E) = k(q) / (r^2),
where k is the electrostatic constant (k = 9 x 10^9 N m^2/C^2), q is the charge, and r is the distance from the charge to the point.

The magnesium nucleus has a charge of +2e, so q = +2e, where e is the elementary charge (e ≈ 1.6 x 10^-19 C). The distance from the magnesium nucleus to the halfway point is 1.5 cm = 0.015 m (half of the given distance of 3 cm).

Let's calculate the electric field due to the magnesium nucleus:
E_magnesium = k(q_magnesium) / (r_magnesium^2)

Step 2: Calculate the electric field due to the 3e charge on the y-axis.
The electric field due to a point charge is also given by Coulomb's law. The charge on the y-axis is 3e, so q = +3e. The distance from the 3e charge to the halfway point is also 1.5 cm = 0.015 m.

Let's calculate the electric field due to the 3e charge:
E_3e = k(q_3e) / (r_3e^2)

Step 3: Calculate the net electric field at the halfway point.
To find the net electric field at the halfway point, we need to sum the individual electric fields due to the magnesium nucleus and the 3e charge since they have the same direction (towards the halfway point).

The net electric field is given by:
E_net = E_magnesium + E_3e

Now, let's substitute the values and calculate the net electric field at the halfway point.